CTET JULY 2019 SYLLABUS NOTIFICATION EXAM DATE
CTET JULY 2019 SYLLABUS NOTIFICATION EXAM DATE: Central Board of Secondary Education New Delhi has been released Notification for CTET Exam July 2019. Board has been Invited Online Application from Qualified Candidates for CTET 2019. CTET Exam will conduct by CBSE on 16/07/2019 at 92 cities. CTET exam will conduct in two sessions i.e. 10:00 a.m. to i.e. 12:30 noon and 2:00 to 4:30 p.m. After implementation of Right to Education act, CTET or State TET is compulsory from July 2009 for candidates who wanted to apply as a teacher from class 1stto 8th . Now qualifying in CTET is a necessary qualification foe a candidate who wants to apply as teacher in CBSE affiliated schools and TET for States.
CTET JULY 2019 SYLLABUS NOTIFICATION EXAM DATE
There are two papers in CTET Exam. Paper Ist consist 150 questions of total 150 marks. This paper is further divided in to five parts, Child Psychology, Language Ist (English or Urdu or Hindi Ist ) Language 2nd (English or Urdu or Hindi 2nd), EVS and Mathematics. This paper is for those, who wanted to become Primary Teacher. The paper 2nd also consist 150 questions of total 150 marks. This paper is further divided in to four parts, Child Psychology, Ist Language (English or Urdu or Sanskrit or Hindi), Language 2nd (English or Urdu or Sanskrit or Hindi 2nd ), Subjects( Science and Mathematics or S. St.). This paper is for those, who wanted to become Junior Basic /Upper Primary (6th to 8th) teacher. Minimum qualifying marks in both papers is 60% each. CTET Exam will conduct by CBSE DELHI every year about in month of September and January. CBSE will also release the answer Key of both papers after 15 days of Examination so one can check his/ her answers through these answers.
CTET JULY 2019 SYLLABUS NOTIFICATION EXAM DATE
Interested and Eligible Candidates Can Apply Online for CTET July 2019 on or up to 12/03/2019. Candidates who want to apply for CTET are also advice to visit Official Web site before Apply. Read Advertisement carefully regarding to Eligibilities, Educational Qualification, Age Limit, Teaching Qualification etc.
IMPORTANT DATES
Notification Date: Tuesday, 05/02/2019
LAST DATE FOR REGISTRATION: Tuesday, 12/03/2019
Last Date to Apply Online: Tuesday, 12/03/2019 till 17:00.
Last Date to Fee Deposit: Friday, 15/03/2018 till 15:30 (Through Net banking)
CTET EXAM DATE: Sunday, 07/07/2019
Paper Ist – Between 09:30 to 12:00 pm
Paper IInd – Between 02:00 to 04:30 pm
Eligibility:
Educational Qualification:
- Graduation in any stream with minimum 50% of Marks
- B.Ed./ BTC/ JBT or equivalent exam
Candidates who are appearing for their qualifying examination, they can also apply for CTET Exam Sep 2018
For Detail SEE NOTIFICATION
Age:
Minimum age for appearing to CTET exam is 21 years maximum age is 31 years.
There is relaxation in upper age for SC/ST/PH/LLM/Ph.D. candidates
Fee:
- Fee of application is Rs 700/ only for only one paper and Rs 1200/ only for both papers for General and OBC candidates
- Rs 350/ only for only one paper and Rs 600/ only for both papers for SC/ST candidates and PWD candidates
CTET JULY 2019 SYLLABUS NOTIFICATION EXAM DATE
Examination Pattern:
PAPER Ist SYLLABUS
PAPER IInd SYLLABUS
How to Apply: Applications are accepted only through online. Apply any other mode will be Rejected.
Process to Apply Online:
- Apply in provided Performa through Official website of CBSECTET
- Visit Official website of CBSECTET
- Select Apply Online
- Fill Online Application Form to Registration
- Take Print out of Fee E-chalan
- Pay Application fee through Any Method
- Fill Online Application Form
- Upload photograph and Sign on provided place
- Take a print out of Application Form
- Keep it Your Self; do not send it any where
For Apply Online CLICK HERE
For Detail CLICK HERE
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